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Cable load port must: Estimates: Multiply the cross-section by 9.5 and add 9. Thirty-five to three-by-five, and both teams lose five points. The conditions are changed and converted, and the high temperature 10% copper upgrade. The number of pipes worn was 234, and the full load was 876. Explanation: In this section, the ampacity (safe current) of various types of insulated wires (rubber and plastic insulated wires) is not directly given, but expressed by "multiplying the cross-section by a certain factor," which is calculated mentally. From Table 53, it can be seen that the multiple decreases as the cross-section increases. "Five to multiply by two at five and nine at a time, and one at a time to go upwards" refers to aluminum-core insulated wires with a cross-section of 2.5 mm² or less, where the current-carrying capacity is approximately 9 times the cross-section. For example, a 2.5 mm² wire has a current-carrying capacity of 2.5 × 9 = 22.5 A. For conductors of 4 mm² and above, the multiple decreases progressively—4×8, 6×7, 10×6, 16×5, and 25×4. "Thirty-five-by-three and five, both groups minus five" means that for 35 mm² wires, the current-carrying capacity is 3.5 times the cross-section, i.e., 35 × 3.5 = 122.5 A. For conductors of 50 mm² or more, the multiple relationship changes—two lines per group, and the multiple decreases by 0.5. So, 50 and 70 mm² wires have 3 times their cross-section, while 95 and 120 mm² wires have 2.5 times. "Conditions are subject to change, high temperature 10% copper upgrade." The above rules apply to aluminum-core insulated wires under an ambient temperature of 25°C. If the wire is used in a higher temperature environment, the ampacity should be reduced by 10%. When replacing aluminum with copper, the copper wire’s ampacity is slightly higher, so you can calculate it as one step larger than the aluminum wire. For example, a 16 mm² copper wire can be treated as a 25 mm² aluminum wire. To select the appropriate cable based on current: The current-carrying capacity depends on the wire’s cross-section, material, model, installation method, and ambient temperature. Many factors influence the calculation, but it can often be done using simple mental math instead of looking up tables. Here are some common rules: - For aluminum-core insulated wires, the current-carrying capacity is roughly 10 times the cross-section for smaller sizes. - 25, 35: four or three times. - 70, 95: 2.5 times. - If the wire is installed in a conduit or in a high-temperature area, reduce the capacity by 20% or 10%, respectively. - Bare wires have 50% higher capacity than insulated ones. - Copper wires are upgraded by one size when calculating from aluminum. For example, a 10 mm² aluminum wire has a current-carrying capacity of 10 × 5 = 50 A. If installed in a conduit, it becomes 50 × 0.8 = 40 A. In high temperature, it’s 50 × 0.9 = 45 A. If both conditions apply, it’s 50 × 0.8 × 0.9 = 36 A. Bare aluminum wires have 50% more capacity than insulated ones. So, a 16 mm² bare wire would have 16 × 4 × 1.5 = 96 A. In high temperature, it’s 16 × 4 × 1.5 × 0.9 = 86.4 A. Copper wires are calculated by upgrading the size. For instance, a 35 mm² bare copper wire is treated as a 50 mm² bare aluminum wire, giving 50 × 3 × 1.5 = 225 A. For high-voltage cables, the same rules apply. A 35 mm² armored aluminum cable has 35 × 3 = 105 A. A 95 mm² cable has 95 × 2.5 = 237.5 A. In a three-phase four-wire system, the neutral wire is typically half the size of the phase wire, but never less than the minimum mechanical strength requirement. In single-phase systems, the neutral and phase wires carry the same current, so they should be the same size.

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