We need to know the certain gearbox parameters. Which parameters do we need to know? This will be explained in detail. What is the check of the thermal power in the reducer? It is the temperature of the surrounding environment. This is a piece of data that we need to analyze. As a reducer, there should be a motor inside. What is the number of stages of this motor, it is not suitable, what is its power, and we need to do in-depth analysis. In addition, the safety factor of the reducer, whether the safety of everyone can be reliably guaranteed, is even more important, and must not be ignored. There is also the fact that the reducer is used on what equipment, and some of the possible results of using it, and it is definitely not a sloppy thing. The calibration of the radial and axial forces of the output shaft of the reducer is also a point to note.
The power of the motor. It should be selected according to the power required by the production machine, and the speed reducer is selected according to the power or torque to be transmitted and the speed required for the work.

The power of the motor. It should be selected according to the power required by the production machinery, and the motor should be operated under the rated load as much as possible. The following two points should be noted when selecting: (1) If the motor power is selected too small. There will be a phenomenon of "small horse-drawn cart", causing long-term overload of the motor. Make its insulation damaged by heat. Even the motor was burned.

(2) If the motor power is selected too large. There will be a "big horse car" phenomenon. The output mechanical power cannot be fully utilized, and the power factor and efficiency are not high, which is not only bad for the user and the power grid. It also causes a waste of electricity.

To correctly select the power of the motor, the following calculations or comparisons must be made: (1) For a constant load continuous operation, if the power of the load (ie, the power on the production machine shaft) is known, Pl(kw). The power P(kw) of the required motor can be calculated as follows: P = P1/n1n2 where n1 is the efficiency of the production machine; n2 is the efficiency of the motor. That is, transmission efficiency. The power obtained by the above formula is not necessarily the same as the power of the product. therefore. The rated power of the selected motor should be equal to or slightly greater than the calculated power. Example: The power of a production machine is 3.95kw. The mechanical efficiency is 70%. If a motor with an efficiency of 0.8 is selected, how much kw should the power of the motor be? Solution=P1/n1n2=3.95/0.7*0.8=7.1kw Since there is no 7.1kw this specification. So choose 7.5kw motor.

(2) Short-time working quota motor. Compared with a motor with the same continuous working rating. The maximum torque is large, the weight is small, and the price is low. Therefore, when conditions permit, try to use a motor with a short-time working quota.

(3) For the motor with intermittent operation quota, the power selection should be based on the magnitude of the load duration, and the motor specially used for the intermittent operation mode should be selected. The calculation formula of the load continuous string Fs% is FS%=tg/(tg+to)×100% where tg is the working time, t. In order to stop the time min; tg ten to the working cycle, and the role of the reducer is to improve the torque, to choose the motor must know the starting torque torque * speed = power and to ensure that the motor is self-locking at rest, can not let the motor Rotate

1.P=W/t

This is a formula for any power, and of course also for mechanical power.

2.P=F*V

This formula only applies to mechanical power.

F is the mechanical power, V is the speed of mechanical uniform motion

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